Qwen3.8 2.4t A95b API

Run qwen/qwen3.8-2.4t-a95b through FastInfra's OpenAI-compatible API. Pay per token, no subscription, routed to the cheapest available provider.

Read the docs
Pricing

Qwen3.8 2.4t A95b pricing

Billed per token used. Prices sync automatically from wholesale providers.

Direction Price per 1M tokens
Input$2.10
Output$6.30
Availability

Served by 4 providers

Requests route to DeepInfra by default (cheapest). Pin a specific provider with the :provider suffix.

Provider Upstream model ID
openrouter qwen/qwen3.8-2.4t-a95b
together Qwen/Qwen3.8-2.4T-A95B
deepinfra Qwen/Qwen3.8-2.4T-A95B
siliconflow Qwen/Qwen3.8-2.4T-A95B
Quickstart

Call Qwen3.8 2.4t A95b in 30 seconds

Works with any OpenAI SDK — change the base URL and API key only.

Python

from openai import OpenAI

client = OpenAI(api_key="YOUR_API_KEY", base_url="https://api.fastinfra.ai/v1")

response = client.chat.completions.create(
    model="qwen/qwen3.8-2.4t-a95b",
    messages=[{"role": "user", "content": "Hello!"}]
)
print(response.choices[0].message.content)

curl

curl https://api.fastinfra.ai/v1/chat/completions \
  -H "Authorization: Bearer YOUR_API_KEY" \
  -H "Content-Type: application/json" \
  -d '{
    "model": "qwen/qwen3.8-2.4t-a95b",
    "messages": [{"role": "user", "content": "Hello!"}]
  }'
FAQ

Qwen3.8 2.4t A95b — common questions

How much does the qwen/qwen3.8-2.4t-a95b API cost?

On FastInfra, qwen/qwen3.8-2.4t-a95b costs $2.1/1M input, $6.3/1M output tokens. Billing is per token used, with no subscription.

Is qwen/qwen3.8-2.4t-a95b compatible with the OpenAI SDK?

Yes. FastInfra exposes qwen/qwen3.8-2.4t-a95b through an OpenAI-compatible endpoint at https://api.fastinfra.ai/v1 — point any OpenAI SDK at that base URL with a FastInfra API key and keep your existing code.

Which providers serve qwen/qwen3.8-2.4t-a95b?

qwen/qwen3.8-2.4t-a95b is available from 4 provider(s): openrouter, together, deepinfra, siliconflow. Requests route to DeepInfra by default (cheapest); append ":provider" to the model ID to pin one.